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35x^2+455x+1260=0
a = 35; b = 455; c = +1260;
Δ = b2-4ac
Δ = 4552-4·35·1260
Δ = 30625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{30625}=175$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(455)-175}{2*35}=\frac{-630}{70} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(455)+175}{2*35}=\frac{-280}{70} =-4 $
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